Finding sum of digits of a number until sum becomes single digit , It contains well written, well thought and well explained computer science and programming Finding sum of digits of a number until sum becomes single digit Given a number n, we need to find the sum of its digits such that: Below is the brute force program to find the sum. Let's see some examples. Hope this Program is useful to you in some sense or other. Finding sum of digits of a number until sum becomes single digit , Below is the brute force program to find the sum. Submitted by Abhishek Pathak, on October 05, 2017 . C Program to find the sum of digits of a number until a single digit is occurred Submitted by Abhishek Jain , on April 09, 2017 In general , we use loop or recursion to traverse each digit of the number and to add them .But it is a complex method (with time complexity O(n)) in comparison to the method describe below (with time complexity O(1)). Python Server Side Programming Programming. For example, Let, n = 2880 Sum of digits = 2 + 8 + 8 = 18: 18 = 1 + 8 = 9. You could define a function to find the sum and keep updating the argument to be the most recent sum until you hit one digit. Here, we combined two statements into a single one which is a feature of Python. Here we are printing sum of given digits till we get the single digit. For the second case, and is always k. Below is the implementation of the above idea : At last print the sum value. In single digit sum, we keep doing sum of digit until a single digit is left. In this program, we first read number from user. Continue the addition process until sum value is a single digit. Digit count value is found by using count function. Then check the sum values digit count is >1. For example, digitalSum(2019) should return 12 because 2+0+1+9=12. The prompt for the problem is as follows: Write a function, persistence, that takes in a positive parameter num and returns its multiplicative persistence, which is the number of times you must multiply the digits in num until you reach a single digit. Given an integer number and we have to keep adding the digits until a single digit is not found. Write a Python program to add the digits of a positive integer repeatedly until the result has a single digit. A digital root is the recursive sum of all the digits in a number. Given n, take the sum of the digits of n. If that value has more than one digit, continue reducing in this way until a single-digit number is produced. After finishing the loop, the sum is displayed. Submitted by Abhishek Pathak, on October 05, 2017 . This is another approach that is a quite similar but concise way to get the sum of digits of a number in Python. When the number is modulo divided by 10 we get the last digit. In this program, we are going to implement logic to find sum of digits until the number is a single digits in C++ programming language. The time complexity of this solution is O(1). A number can be of the form 9x or 9x + k. For the first case, answer is always 9. Write a Python program to add the digits of a positive integer repeatedly until the result has a single digit. Let's see the steps to solve the problem. At last print the sum value. If a number n is divisible by 9, then the sum of its digit until sum becomes single digit is always 9. Given n, take the sum of the digits of n. If that value has more than one digit, continue reducing in this way until a single-digit number is produced. Python Program to Find the Sum of Digits of a Number using While loop In this method, we use the while loop to get the sum of digits of the number. 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